Question

4x=2y
2x+3y=1
sistema pela regra de Cramer​

Answer 1

Pelo método de Cramer :

4x-2y=0

2x+3y=1

(4 -2)

(2 3)

D= 3.(4)-2.(-2)

D=12+4

D=16

(0 -2)

(1 3)

Dx=3.(0)-1.(-2)

DX=0+2

DX=2

(4 0)

(2 1)

Dy=1.(4)-0.(2)

Dy=4-0

Dy=4

X=DX/D=2/16=1/8

Y=Dy/D=4/16= 1/4

Resposta :

x=1/8 e y= 1/4