Question

50+{10-2x[(6+4:2)-(10-3)]}​

Answer 1

50+{10-2×[(6+4:2)-(10-3)]}=

50+{10-2×[(6+2)-(10-3)]}=

50+{10-2×[8-(10-3)]}=

50+{10-2×[8-7]}=

50+{10-2×1}=

50+{10-2}=

50+8=

58