Question

descubra o valor de x e y.
4^×.8^y=1/4 (fração)
9^×.27^2y=3

me ajudem! ​

Answer 1

${4}^{x}. {8}^{y} = \frac{1}{4} \\ {9}^{x}. {27}^{2y} = 3 \\ {2}^{2x}. {2}^{3y} = {2}^{ - 2} \\ {3}^{2x} {3}^{6y} = {3}^{1}$

${2}^{2x + 3y} = {2}^{ - 2} \\ {3}^{2x + 6y} = {3}^{1}$

$2x + 3y = - 2 \times ( - 1)\\ 2x + 6y = 1 \\ - 2x - 3y = 2 \\ 2x + 6y = 1$

$2x - 2x + 6y - 3y = 1 + 2 \\ 3y = 3 \\ y = \frac{3}{3} \\ y = 1$

$2x + 6y = 1 \\ 2x + 6.1 = 1 \\ 2x + 6 = 1 \\ 2x = 1 - 6 \\ 2x = - 5$

$x = - \frac{5}{2}$

S={–5/2,1}