Question

Qual a distancia do ponto P (-2,1) á reta 4x+3y-2=0​

Answer 1

A fórmula de distância de um ponto à reta é:

$d=\frac{|ax' + by' + c|}{\sqrt{a^{2} + b^{2}}}$

Para o ponto P(x';y')

$d=\frac{|4.-2+3.1-2|}{\sqrt{4^{2} + 3^{2}}}\\d=\frac{|-7|}{\sqrt{25}}\\d=\frac{7}{5}$

Answer 2

$Dp,r=\frac{|axp+byp+c|}{\sqrt{x^2+y^2}} \\ Dp,r=\frac{|4.(-2)+3.1+(-2)|}{\sqrt{4^2+3^2}}$

$Dp,r=\frac{7}{5}$