Question

${x }^{2} - 4x - 12 = 0$
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Answer 1

x²-4x-12=0

a=1

b=-4

c=-12

∆=b²-4.a.c

∆=(-4)²-4.(1).(-12)

∆=16+48

∆=64

x'=[-(-4)+√64]/2.(1)

x'=[4 +8]/2

x'=12/2

x'=6

x'=[-(-4)-√64]/2.(1)

x'=[4 -8]/2

x"=-4/2

x"=-2

Resposta :

S={( -2 ; 6)}