a) -11x2 + 44 = 0 b) x2 + 100 = 0 c)15x2 – 45x = 0 d) 72x2 + 81x = 0
e) x2 – 8x +
12 = 0 f) 2x2 – 5x –
3 = 0 g) 5x2 –
3x + 1 = 0
cassio163:
QUal a pergunta? Onde tem o x2 é x² (x ao quadrado) ?
Respostas
respondido por:
0
a)-11x+46=x=46/11=4,18
respondido por:
3
a) -11x² + 44 = 0
-11x² = - 44
x² = - 44/ - 11
x = √4
x = 2
b) x² + 100 = 0
x² = - 100
x = ± √100
x = ± 10
c) 15x² – 45x = 0
x(15x - 45) = 0
x = 0
15x - 45 = 0
15x = 45
x = 45/15
x = 3 S= {0 , 3}
d) 72x² + 81x = 0
x (72x + 81) = 0
x = 0
72x + 81 = 0
72x = 81
x = 81/72
x = 9/8
S = {0, 9/8}
e) x² – 8x +12 = 0
∆ = 8^2 - 4 * 1 * 12
∆ = 64 - 48
∆ = 16
√∆ = 4
x' = (8 + 4)/2
x' = 6
x" = (8 - 4)/2
x" = 2
S = {2, 6}
f) 2x² – 5x –3 = 0
a= 2
b= 5
c= -3
Δ= b²-4ac
Δ= 5²-4.2.(-3)
Δ= 25-4.2.(-3)
Δ= 25-8.(-3)
Δ= 25+24
Δ= 49
x= -b±√∆/2a
x= -5±√49/2.2
x= -5±7/4
x' = -5+7/4 = 2/4 = 1/2
x'' = -5-7/4 = -12/4 = -3
S = {1/2,-3}
g) 5x² –3x + 1 = 0
x²-3x-2=0
Δ= b² - 4ac
Δ= (-3)² - 4*5(-2)
Δ= 9 + 40= 49
Δ= 49
x= - b ± √∆ / 2a
x= - (- 3) ± √49 / 2*5
x' = 3+7 / 10
x'= 10/10 = 1
x" = 3 - 7 / 10
x"= -4/10=-2/5
S = {1/2,-3}
-11x² = - 44
x² = - 44/ - 11
x = √4
x = 2
b) x² + 100 = 0
x² = - 100
x = ± √100
x = ± 10
c) 15x² – 45x = 0
x(15x - 45) = 0
x = 0
15x - 45 = 0
15x = 45
x = 45/15
x = 3 S= {0 , 3}
d) 72x² + 81x = 0
x (72x + 81) = 0
x = 0
72x + 81 = 0
72x = 81
x = 81/72
x = 9/8
S = {0, 9/8}
e) x² – 8x +12 = 0
∆ = 8^2 - 4 * 1 * 12
∆ = 64 - 48
∆ = 16
√∆ = 4
x' = (8 + 4)/2
x' = 6
x" = (8 - 4)/2
x" = 2
S = {2, 6}
f) 2x² – 5x –3 = 0
a= 2
b= 5
c= -3
Δ= b²-4ac
Δ= 5²-4.2.(-3)
Δ= 25-4.2.(-3)
Δ= 25-8.(-3)
Δ= 25+24
Δ= 49
x= -b±√∆/2a
x= -5±√49/2.2
x= -5±7/4
x' = -5+7/4 = 2/4 = 1/2
x'' = -5-7/4 = -12/4 = -3
S = {1/2,-3}
g) 5x² –3x + 1 = 0
x²-3x-2=0
Δ= b² - 4ac
Δ= (-3)² - 4*5(-2)
Δ= 9 + 40= 49
Δ= 49
x= - b ± √∆ / 2a
x= - (- 3) ± √49 / 2*5
x' = 3+7 / 10
x'= 10/10 = 1
x" = 3 - 7 / 10
x"= -4/10=-2/5
S = {1/2,-3}
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