Question

determine o perímetro do paralelogramo ABCD obs : (não tem E ) só ABCD​

Answer 1

$\tan(60) = \frac{MC}{MB} \\ \sqrt{3} = \frac{4}{MB} \\ MB = \frac{4}{ \sqrt{3} } = \frac{4 \sqrt{3} }{3}$

$\sin(60) = \frac{MC}{BC} \\ \frac{ \sqrt{3} }{2} = \frac{4}{ BC} \\ BC = \frac{8}{ \sqrt{3} } = \frac{8 \sqrt{3} }{3}$

$p = 2.(15 + \frac{4 \sqrt{3} }{3} + \frac{8 \sqrt{3} }{3}) \\ p = 2(15 + 4 \sqrt{3})cn$