Question

Calcule os valores de x para:

Answer 1

Resposta:

Explicação passo-a-passo:

$a) \ x^2=12^2+10^2=>x=\sqrt{12^2+10^2}=> x=\sqrt{244}=>x=2\sqrt{61}\\b) \ 8^2=6^2+x^2=>64-36=x^2=>x=\sqrt{28}=>x=2\sqrt{7}\\c) \ 11^2=x^2+9^2=>121=x^2+81=>121-81=x^2=>x=\sqrt{40}=>x=2\sqrt{10}\\d) \ x^2=(\sqrt{5} )^2+(\sqrt{5})^2=>x^2=\sqrt{5^2}+\sqrt{5^2}=>x^2=\sqrt{25}+\sqrt{25}=>x=\sqrt{10}\\e) \ (\sqrt{29})^2=x^2+4^2=>\sqrt{29^2}=x^2+16=>29-16=x^2=>x=\sqrt{13}\\f) \ x=\sqrt{24^2+20^2}=>x=\sqrt{576+400}=>x=\sqrt{976}=>x=2^4\sqrt{61}$