Question

resolva
a)x(2x-1) + 6= 4(x+1)

Answer 1

x(2x-1)+6=4(x+1)
2x^2-x+6=4x+4
2x^2-x-4x+6-4
2x^2-5x+2=0
delta=b^2-4ac
delta=(-5)^2-4.2.2
delta=25-16
delta=9
x=-b-/+ raiz de delta/2a
x=-(-5)-3/2.2
x=5-3/4
x=2/4 (:2)
x=1/2
x=-(-5)+3/2.2
x=5+3/4
x=8/4
x=2

Answer 2

3x^2-x+6=4x+4
3x^2-4x=4-6
3x^2-5x=-2 

Bháskara
25-4.3.-2=
25-24=1
x'=5+1/6=1
x''=5-1=4/6 /2 = 2/3