Question

Dadas as funções:
Assim, z(x) = f’(x)+g’(x)+h’(x) é igual a:

Answer 1

f(x) = 3.x² -2.Cos(x)

f'(x) = 3.2.x¹ -2.( -Sen(x))

f'(x) =  6.x +2.Sen(X)

g(x) = x³.Cos(x)

g'(x) = (x³)'.Cos(x) +x³.(Cos(x))'

g'(x) = 3.x².Cos(x) -x³.Sen(x)

h(x) = x.Sen(x) / 1 +x

h'(x) = (x.Sen(x))'.(1+x) -x.Sen(x).(1+x)' / ( 1 +x)²

h'(x) = ( 1.Sen(x) +x.Cos(x)).(1+x) -x.Sen(x).1 / ( 1 +x)²

h'(x) = Sen(x) +x.Sen(x) +x.Cos(x) +x².Cos(x) -x.Sen(x) / (1 +x)²

h'(x) = Sen(x) +(x²+x).Cos(x) / ( 1 +x)²

z(x) = 6.x +2.Sen(x) +3.x².Cos(x) -x³.Sen(x) + [Sen(x) +(x²+x).Cos(x)] / ( 1 +x)²

 Logo a letra certa é a E

Dúvidas só perguntar XD

Answer 2

Resposta:

f(x) = 3.x² -2.Cos(x)

f'(x) = 3.2.x¹ -2.( -Sen(x))

f'(x) =  6.x +2.Sen(X)

g(x) = x³.Cos(x)

g'(x) = (x³)'.Cos(x) +x³.(Cos(x))'

g'(x) = 3.x².Cos(x) -x³.Sen(x)

h(x) = x.Sen(x) / 1 +x

h'(x) = (x.Sen(x))'.(1+x) -x.Sen(x).(1+x)' / ( 1 +x)²

h'(x) = ( 1.Sen(x) +x.Cos(x)).(1+x) -x.Sen(x).1 / ( 1 +x)²

h'(x) = Sen(x) +x.Sen(x) +x.Cos(x) +x².Cos(x) -x.Sen(x) / (1 +x)²

h'(x) = Sen(x) +(x²+x).Cos(x) / ( 1 +x)²

z(x) = 6.x +2.Sen(x) +3.x².Cos(x) -x³.Sen(x) + [Sen(x) +(x²+x).Cos(x)] / ( 1 +x)²

Explicação passo a passo:

resposta certa é a E