Question

х³у - 3xy + 2у² - 3
а) para x = 0 e y = 1​

Answer 1

x=0

y=1

${x}^{3}y-3xy+2{y}^{2}-3 \\ {0}^{3}.1-3.0.1+2.{1}^{2}-3= 2-3=-1$

Answer 2

Para x = 0 e y = 1

------------------------------

x²y - 3xy + 2y² - 3 =

0².1 - 3.0.1 + 2.1² - 3 =

0 - 0 + 2.1 - 3 =

0 + 2 - 3 =

-1