Question

calcule a distância entre os pontos A e B . A(-2,6) e B(3,18)​

Answer 1

Resposta:

Explicação passo-a-passo:

$Dab \sqrt[tex]\sqrt (3-(-2)^2+(6-18)^2\\\sqrt(5)^2+(-12)^2\\\\sqrt25+144\\\sqrt169 =13$ (xb-xa)^2+(yb-ya)^2[/tex]

Answer 2

$\large\boxed{\begin{array}{l} \sf{d_{AB }=\sqrt{(x_{A} -x_{B})^{2}+(y_{A} -y_{B})^{2}}} \\ \sf{d_{AB } = \sqrt{(( - 2) - 3) {}^{2} + (6 - 18) {}^{2} } } \\ \sf{d_{AB } = \sqrt{( - 5) {}^{2} + ( - 12) {}^{2} } } \\ \sf{d_{AB } = \sqrt{25 + 144} } \\ \sf{d_{AB } = \sqrt{169} } \\ \huge \boxed{ \boxed { \boxed{ \boxed{ \sf{d_{AB } = 13}}}}}\end{array}}$