Question

1. calcule o valor de x nos triângulos retângulos

Answer 1

Resposta:

a) ± 10

b) ± 15

c) ± 3

d) ± 4

Explicação passo-a-passo:

$a) x^2=8^2+6^2\\  \ x^2=64+36\\x=\frac{+}{-}\sqrt{100} \\x=\frac{+}{-}10\\ \\b)x^2=12^2+9^2\\x^2= 144+81\\x=\frac{+}{-} \sqrt{225} \\x=\frac{+}{-}15\\ \\c) 5^2=4^2+x^2\\25=16+x^2\\25-16=x^2\\x=\frac{+}{-}\sqrt{9}\\x=\frac{+}{-}3\\ \\d)20^2=(4x)^2+(3x)^2\\400=16x^2+9x^2\\400=25x^2\\\frac{400}{25}=x^2\\x=^+_{-}\sqrt{16}\\x=^+_{-}4$