Question

seja a equacoa x(x+11)=-24.

Answer 1

x²+11x+24=0

Δ = b2 - 4.a.c
Δ = 112 - 4 . 1 . 24
Δ = 121 - 4. 1 . 24
Δ = 25 Há 2 raízes reais.

x = (-b +- √Δ)/2a

x' = (-11 + √25)/2.1  
x' = -6 / 2  
x' = -3 

x'' = (-11 - √25)/2.1
x'' = -16 / 2
 x'' = -8

Answer 2

x2+11x=-24
x2+11x+24=0
delta=b2-4ac
delta=11^2-4*1*24
delta=121-96
delta=25


X=-11+- raiz quadrada de 25/2*1
x=-11+- 5/2
x'=-11+5/2
x'=-6/2=  x'=-3

x''=-11-5/2 
x''=-16/2
x''=-8