Question

Simplifique as expressões.
a)n! /(n-1)!=
b)(n+4)! /(n+2)!+(n+3)!=
c)(n-1)!+n!/(n+1)!=
​

Answer 1

Explicação passo-a-passo:

Oii tudo bem?

A) n!/(n-1)! = n(n-1)! / (n-1)! = n

B) (n+4)! / (n+2)! + (n+3)! = n+4+n+3/ (1 + n+3) = 2n+7/n+4

C) (n-1)! + n(n-1)!/(n+1)n(n-1)! = n+1 / n(n+1)

Espero ter ajudado!