Question

Como calcular o limite?
$\lim_{x \to \ -1} \frac{x^3-6x^2+10x+17}{x^2+x}$

Answer 1

Prezada.

Temos:

$\lim_{x \to \\-1}= \frac{x^3-6x^2+10x+17}{x^2+x}$

Logo:

$\lim_{x \to \-1}= \frac{3x^2-12x+10}{2x+1} \\ \lim_{x \to \-1} = \frac{3*(-1)^2-12(-1)+10}{2(-1)+1 \\ } \\ \lim_{x \to \-1}= \frac{25}{-1} \\ \boxed{\boxed{ \lim_{x \to \-1} = -25}}$