Question

hipotenusa 13 cateto x cateto x+7​

Answer 1

Explicação passo-a-passo:

hip^2= cat^2+ cat^2

(13)^2= x^2+(x+7)^2

169= x^2+ x^2+14x+49

2x^2+14x+49-169= 0

2x^2+14x-120= 0 ÷(2)

x^2+7x-60= 0

∆= b^2-4.a.c

∆= (7)^2-4.1.(-60)

∆= 49+240

∆=289

x= -b+-√∆

__-----------

____2.a

x= -7+-√289

__--------------

____2.1

x'= -7+17

__--------

____2

x'= 10/2

x'= 5

x"= -7-17

___------

_____2

x"= -24/2

x"= -12