Question

qual o valor de delta na equação 3x²-6x=0​

Answer 1

3x² - 6x = 0

A= 3

B= - 6

C= 0

∆= b² - 4ac

∆= ( - 6)² - 4 • 3 • 0

∆= 36 - 0

∆= 36 --> valor de Delta

x= - b ± √∆/2a

x= - ( - 6) ± √36/2 • 3

x= 6 ± 6/6

x'= 6 + 6/6 = 12/6 = 2

x''= 6 - 6/6 = 0/6 = 0

S= ( 0 , 2)