Resposta: Explicação passo-a-passo: 2)\\a)y=\frac{4x}{10}+\frac{1}{6}\\\\\frac{4x}{10}+\frac{1}{6}=0\\\\\frac{4x}{10}=-\frac{1}{6}\\\\(-24x=-10)*(-1)\\24x=10\\x=\frac{10}{24}=>x=\frac{5}{12}\\\\b)f(x)=-4x-3\\-4x-3=0\\-4x=3\\x=-\frac{3}{4} 3)g(x)=\frac{7}{5}x-3\\\\a)g(-4)=\frac{7}{5}*(-4)-3\\\\g(-4)=-\frac{28}{5}-3\\\\g(-4)=-\frac{43}{5}\\\\b) \ g(\frac{5}{2})=\frac{7}{5}*\frac{5}{2}-3\\\\g(\frac{5}{2})=\frac{35}{10}-3\\\\g(\frac{5}{2})=\frac{5}{10}=>x=\frac{1}{2}

Matéria: Matemática
Autor: eriksouza24
Perguntado 7 anos atrás

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me ajudem por favor

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respondido por: andersonleonel

Resposta:

Explicação passo-a-passo:

$2)\\a)y=\frac{4x}{10}+\frac{1}{6}\\\\\frac{4x}{10}+\frac{1}{6}=0\\\\\frac{4x}{10}=-\frac{1}{6}\\\\(-24x=-10)*(-1)\\24x=10\\x=\frac{10}{24}=>x=\frac{5}{12}\\\\b)f(x)=-4x-3\\-4x-3=0\\-4x=3\\x=-\frac{3}{4}$

$3)g(x)=\frac{7}{5}x-3\\\\a)g(-4)=\frac{7}{5}*(-4)-3\\\\g(-4)=-\frac{28}{5}-3\\\\g(-4)=-\frac{43}{5}\\\\b) \ g(\frac{5}{2})=\frac{7}{5}*\frac{5}{2}-3\\\\g(\frac{5}{2})=\frac{35}{10}-3\\\\g(\frac{5}{2})=\frac{5}{10}=>x=\frac{1}{2}$