Question

Urgente me ajudeem porfavor!
Calcule: De A) até H)... (Façam pelo menos os que souberem, é urgentee)
$A) \frac{7c-21}{ c^{2}-6c+9 } \\ \\ B) \frac{5x-15}{10x} \\ \\C) \frac{7a}{7x-14} \\ \\D) \frac{15x-3y}{3x-3y} \\ \\E) \frac{ x^{2} -xy}{x-y} \\ \\F) \frac{ x^{2} y}{xy} \\ \\ G) \frac{10m}{2m} \\ \\H) \frac{x-9}{7x-63}$

Answer 1

a) $\frac{7c-21}{c^2-6c+9} = \frac{7(c-3)}{(c-3)^2} = \frac{7}{c-3}$

b) $\frac{5x-15}{10x} = \frac{5(x-3)}{10x} = \frac{x-3}{2x}$

c) $\frac{7a}{7x-14} = \frac{7a}{7(x-2)} = \frac{a}{x-2}$

d) $\frac{15x-3y}{3x-3y} = \frac{3(5x-y)}{3(x-y)} = \frac{5x-y}{x-y}$

e) $\frac{x^2-xy}{x-y} = \frac{x(x-y)}{x-y} =x$

f) $\frac{x^2y}{xy} = \frac{x.xy}{xy} =x$

g) $\frac{10m}{2m} =5$

h) $\frac{x-9}{7x-63} = \frac{x-9}{7(x-9)} = \frac{1}{7}$