Question

considere log2=0,3, log3= 0,4 e log5=0,7 determine a) log 60 b) log 8/5​

Answer 1

$log(60) =$

$log(3 \times 2\times 2 \times 5) =$

$log(3) + log(2) + log(2) + log(5) =$

$0.4 + 0.3 + 0.3 + 0.7 = 1.7$

a) log60=1,7

$log( \frac{8}{5} ) =$

$log(8) - log(5) =$

$log(2 \times 2 \times 2) - log(5 ) =$

$log(2) + log(2) + log(2) - log(5) =$

$0.3 + 0.3 + 0.3 - 0.7 = 0.2$

b) log(8/5)= 0,2