Question

2^(3x+2)/8^(2x+7) =4^(x-1)

Answer 1

$\frac{ 2^{3x+2} }{ 8^{2x+7} } = 4^{x-1}$

$\frac{ 2^{3x+2} }{ 2^{6x+21} } = 2^{2x-2}$


$2^{3x+2-6x-21} = 2^{2x-2}$

$3x+2-6x-21 = 2x-2 -3x - 19 = 2x -2 -3x -19 + 2 = 2x -3x -17 = 2x -3x -2x = 17 -5x = 17 .(-1) 5x = -17 x = -17/5$

Answer 2

2^(3x + 2) / 2^3(2x + 7) = 2^2(x - 1)
2^(3x + 2) = 2^(6x + 21) * 2^(2x - 2)
2^(3x + 2) = 2^6x + 21 + 2x - 2
3x + 2 = 6x + 21 + 2x - 2
3x - 6x - 2x = 21 - 2 - 2
- 3x - 2x = 19 - 2
- 5x = 17 .(-1)
5x = - 17
x = - 17/5