Question

Simplifique:
me ajude ai​

Answer 1

Resposta:

a)

n!/(n+2)!

n!/(n+2)*(n+1)n!

=1/[(n+2)*(n+1)]

b)

(n+1)!/(n-1)!

=(n+1)n(n-1)!/(n-1)!

=(n+1)n=n²+n

c)

(n+2)!

(n+2)(n+1)n!/n!  

=(n+2)(n+1)

d)

(n+1)!/n!

=(n+1)n!/n!=n+1