Question

$a) \frac{5x - 4}{6} = 6$

$b) \frac{x}{2} + \frac{x}{6} = 4$


$c) \frac{x}{2} + \frac{x}{3} + \frac{x}{4} = 13$

resolva a equação de 1° grau com urgência por favor ​

Answer 1

$\frac{5x - 4}{6} = 6 \\ mutiplique \: ambos \: os \: numeros \: por \: 6 \\ 5x - 4 = 36 \\ mova \: as \: constantes \: para \: a \: direita \: \\ 5x = 36 + 4 \\ 5x = 40 \\ x = 3 \\ b) \\ \frac{x}{2} + \frac{x}{6} = 4 \\ 3x + x = 24 \\ 4x = 24 \\ x = 6 \\ c) \\ \frac{x}{2} + \frac{x}{3} + \frac{x}{4} = 13 \\ x + 4x + 3x = 156 \\ 3x = 56 \\ x = 12 \: fim \:$

peço ajuda agradecendo

Answer 2

a)

$\boxed{\frac{5x - 4}{6} = 6}$

$5x-4 =6.6$

$5x-4=36$

$5x=36+4$

$5x=40$

$x=\frac{40}{5}$

$\boxed{\boxed{x=8}}$

b)

$\boxed{\frac{x}{2} + \frac{x}{6} = 4}$

$\frac{x}{2} + \frac{x}{6} = 4\times(6)$

$3x +x =24$

$4x=24$

$x=\frac{24}{4}$

$\boxed{\boxed{x=6}}$

c)

$\boxed{\frac{x}{2} + \frac{x}{3} + \frac{x}{4} = 13}$

$\frac{x}{2} + \frac{x}{3} + \frac{x}{4} = 13\times(12)$

$6x+4x+3x=156$

$13x=156$

$x=\frac{156}{13}$

$\boxed{\boxed{x=12}}$