Question

2 elevado 4x+1 ×8 elevado 3-x=1/16

Answer 1

Resposta:

${2}^{4x + 1} \times {8}^{3 - x} = \frac{1}{16} \\ \\ {2}^{4x + 1} \times { ({2}^{3}) }^{3 - x} = {16}^{ - 1} \\ \\ {2}^{4x + 1} \times {2}^{9 - 3x} = {2^{ - 4}} \\ \\ {2}^{4x + 1 + 9 - 3x} = {2}^{ - 4} \\ \\ 4x + 1 + 9 - 3x = - 4 \\ \\ x + 10 = - 4 \\ x = - 4 - 10 \\ x = - 14$