• Matéria: Matemática
  • Autor: meilewis01q
  • Perguntado 7 anos atrás

calcule x nas figuras a seguir:

Anexos:

Respostas

respondido por: darzaberg2
7

Resposta:

a) 110

b) 92

Explicação passo-a-passo:

soma dos angulos de um poligono

Sₙ = ( n - 2 ) 180

5 lados

S₅= 3 .180 = 540

A) x + 100 + 120 + 110 + 100 = 540

x = 110

B) x -20 + 143 + x + 143 + 90 = 540

2x = 184

x = 92


meilewis01q: mt obrigada
respondido por: CyberKirito
6

Soma dos ângulos internos de um polígono qualquer

\boxed{S_{i}=(n-2).180\degree}

a) S_{i}=(n-2).180\degree

S_{i}=(5-2).180\degree

S_{i}=3.180\degree=540\degree

100\degree+110\degree+120\degree+100\degree+x=540\degree

x+430\degree=540\degree\\x=540\degree-430\degree

\boxed{\boxed{x=110\degree}}

b)

x-20\degree+143\degree+x+143\degree+90\degree=540\degree

2x+356\degree=540\degree\\2x=540\degree-356\degree\\2x=184\degree

x=\frac{184\degree}{2}

\boxed{\boxed{x=92\degree}}


meilewis01q: mt obrigada
CyberKirito: De nada
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