Question

resolva as equaçoes (com Log)

Answer 1

Resposta:

$log_{5} (4x-3) = 1\\5^{1} = 4x-3\\5= 4 x -3\\4x = 5 + 3\\4x = 8\\x=\frac{8}{4} \\\\x = 2\\log_{\frac{1}{2} } (3 + 5x) = 0 \\\frac{1}{2}^{0} = 3 + 5x \\1 = 3+ 5x\\1 - 3 = 5x\\-2 =5 x\\5x = -2 \\\\\\x = -\frac{2}{5}$