Question

seja m=0,03+√49- (4÷3/2) o valor de m é​

Answer 1

$m=0,03+\sqrt{49}-(4\div\frac{3}{2})$

$m=0,03+7-(4.\frac{2}{3})$

$m=0,03+7-\frac{8}{3}$

$m=\frac{3}{100}+7-\frac{8}{3}=\frac{9+2100-800}{300}$

$\boxed{\boxed{m=\frac{1309}{300}}}$