Question

como resolver essa fração?
f) (n-1)!
/(n+1)!

Answer 1

 n! = n.(n-1).(n-2). ... .3.2.1  

• n ∈ N

f -

$\frac{(n-1)!}{(n+1)!}\\\\\frac{(n-1)!}{(n+1).n.(n-1)!}\\\\\frac{1}{n.(n+1)}\\\\\frac{1}{n^2+n}$

Dúvidas só perguntar!

Answer 2

Resposta:

n! = n.(n-1).(n-2). ... .3.2.1  

n ∈ N

f -

\frac{(n-1)!}{(n+1)!}\\\\\frac{(n-1)!}{(n+1).n.(n-1)!}\\\\\frac{1}{n.(n+1)}\\\\\frac{1}{n^2+n}