Question

Resolva i33-i100/i12

Answer 1

• de acordo com o enunciado:

 i^33 = i^(32 + 1) = i

 i^100 = i^(100 + 0) = 1

 i^12 = i^(12 + 0) = 1

i^33- ( i^100/i^12) = i - 1

Answer 2

$\frac{{i}^{33}-{i}^{100}}{{i}^{13}}$

$\frac{\textcolor{green} {\cancel{{i}^{33}}^{{i}^{21}}}(1-{i}^{67})}{\textcolor{blue}{\cancel{{i}^{12}}}}$

${i}^{21}={i}^{1}=i$

${i}^{67}={i}^{3}=-i$

$-1(1-(-i)) =\textcolor{blue}{-1(1+i)} \textcolor{green}{\checkmark}$