Question

Sendo:
A = x²-2ax+a²;
B = 5x²+3ax-4a²;
C = x²-ax+2a²;
Calcula: A) A + B + C
B) - ( - A) -B - C

Answer 1

Olá, tudo bem?

A = x²-2ax+a²

B = 5x²+3ax-4a²

C = x²-ax+2a²

a) A + B + C

= (x² — 2ax + a²) + (5x² + 3ax — 4a²) + (x² — ax + 2a²)

= x² — 2ax + a² + 5x² + 3ax — 4a² + x² — ax + 2a²

= 7x² + 0ax — 3a²

= 7x² — a²

b) — (— A) — B — C

= + A — B — C

= x² — 2ax + a² — (5x² + 3ax — 4a²) — (x² — ax + 2a²)

= x² — 2ax + a² — 5x² — 3ax + 4a² — x² + ax — 2a²

= x² — 5x² — x² — 2ax — 3ax + ax + a² + 4a² — 2a²

= —5x² — 4ax + 3a²

Espero ter ajudado!