Question

c) ² - 8x +16=0 fórmula de Bhaskara ​

Answer 1

Resposta:

a) 1 b) -8 ) 16

${x}^{2} - 8x + 16 = 0$

$x = \frac{ - b + - \sqrt{ {b}^{2} - 4 \times a \times c } }{2 \times a}$

$x = \frac{ - ( - 8) + - \sqrt{( - 8)^{2} - 4 \times 1 \times 16 } }{2 \times 1}$

$x = \frac{8 + - \sqrt{64 - 64} }{2}$

$x = \frac{8 + - \sqrt{0} }{2}$

$x = \frac{8 + - 0}{2}$

$x1 = \frac{8 + 0}{2} \\ x1 = \frac{8}{2} \\ x1 = 2$

$x2 = \frac{8 - 0}{2} \\ x2 = \frac{8}{2} \\ x2 = 4$