Question

Calcule o valor de x​

Answer 1

Ola!

Teorema de Pitágoras:

${16}^{2} = {x }^{2} + {(4 \sqrt{2} )}^{2} \\ 256 = {x}^{2} + 16 \times 2 \\ 256 = {x}^{2} + 32 \\ - {x}^{2} = 32 - 256 \\ - {x}^{2} = - 224 \: \cdot( - 1) \\ {x}^{2} = 224 \\ \sqrt{ {x}^{2} } = \sqrt{224} \\ \bf{x =4 \sqrt{14} }$