Question

Sendo a = 10, b = $2^{1/2}$ e c = 8. Calcule
$\sqrt{b^{2} -4 a.c$

Answer 1

Explicação passo-a-passo:

$a=10\\ \\ b=2^{1\over2}=\sqrt{2} \\ \\ c=8\\ \\ \sqrt{b^2-4ac} =\\ \\ \sqrt{(\sqrt{2} )^2-4(10)(8)} =\\ \\ \sqrt{2-320} =\sqrt{-318}$