Question

coloque na forma ax²+bx+c=0
a- (x-5)² - 9=0
b- (x+1)²- x =7
c- (x+4)² = 3 (x+2)=
d- (x-2) (x+1) = 3
e- 4x²-1 = (x+3) (x-3)

Answer 1

a- (x-5)² - 9=0 
x²+25-9=0

b) (x+1)²- x =7
x²+1-x=7
x²-x=7-1
x²-x=6
x²-x-6 =0

c) (x+4)² = 3 (x+2)= 
x²+16=3x+6
x²-3x=6-16
x²-3x=-16
x²-3x+16=0

d- (x-2) (x+1) = 3 
x²+x-2x-2=3
x²-x=3+2
x²-x=5
x²-x=5
x²-x-5=0

e) 4x²-1 = (x+3) (x-3)
4x²-1=x²-3x-9
4x²-x²+3x=-9+1
3x²+3x=-8
3x²+3x+8=0