Question

contrua amatriz a i j de orde 4×5 sendo a i j = 3i+2j​

Answer 1

$A=\begin{bmatrix}a_{11}&a_{12}&a_{13}&a_{14}&a_{15}\\a_{21}&a_{22}&a_{23}&a_{24}&a_{25}\\a_{31}&a_{32}&a_{33}&a_{34}&a_{35}\\a_{41}&a_{42}&a_{43}&a_{44}&a_{45}\end{bmatrix}$

$a_{11}=3.1+2.1=5\\a_{12}=3.1+2.2=3+4=7\\a_{13}=3.1+2.3=3+6=9$

$a_{14}=3.1+2.4=11\\a_{15}=3.1+2.5=13$

$a_{21}=8\\a_{22}=10\\a_{23}=12$

$a_{24}=14\\a_{25}=16$

$a_{31}=11\\a_{32}=13\\a_{33}=15$

$a_{34}=17\\a_{35}=19$

$a_{41}=14\\a_{42}=16\\a_{43}=18$

$a_{44}=20\\a_{45}=22$

$A=\begin{bmatrix}5&7&9&11&13\\8&10&12&14&16\\11&13&15&17&19\\14&16&18&20&22\end{bmatrix}$