Question

sistema 3v1-5v2=10-2v1
v1+2v2=50

Answer 1

$\begin{cases}3v_{1}-5v_{2}=10-2v_{1}\\v_{1}+2v_{2}=50\end{cases}$

$\begin{cases}3v_{1}+2v_{1}-5v_{2}=10\\v_{1}+2v_{2}=50\end{cases}$

$\begin{cases}5v_{1}-5v_{2}=10\\v_{1}+2v_{2}=50\end{cases}$

$+\begin{cases}2v_{1}-2v_{2}=4\\v_{1}+2v_{2}=50\end{cases}$

$3v_{1}=54\\v_{1}=\frac{54}{3}\\v_{1}=18$

$v_{1}+2v_{2}=50\\18+2v_{2}=50\\2v_{2}=50-18$

$2v_{2}=32\\v_{2}=\frac{32}{2}\\v_{2}=16$

$s=\left\{(18,16)\right\}$