Question

(FUVEST) $\sqrt[3]{\frac{2^{28} + 2^{30}}{10} } =$

a) $\frac{2^{8}}{5}$
b) $\frac{2^{9}}{5}$
c) $2^{8}$
d) $2^{9}$
e) $(\frac{2^{58}}{10})^{\frac{1}{3} }$

Answer 1

Resposta:

         2^9         (opção:  d)

Explicação passo-a-passo:

.

.    =   [ (2^28  +  2^30) / 10 ] ^1/3

.    =   [ 2^28.(1 + 2²) / 10 ] ^1/3

.    =   [ 2^28.(1 + 4) / 2.5 ] ^1/3

.    =   [ 2^28 . 5 / 2.5 ] ^1/3

.    =   [ 2^27 ] ^1/3

.    =   2^27.1/3

.    =   2^27/3

.    =   2^9

.

(Espero ter colaborado)

Answer 2

Solução:

$\sqrt[3]{\frac{ 2^{28} + 2^{30} }{10} } = \sqrt[3]{\frac{ 2^{28}(1+2^{2}) }{10} } = \sqrt[3]{\frac{ 2^{28} . 5 }{10} } = \sqrt[3]{\frac{ 2^{28}}{2} } = \sqrt[3]{2^{27} } } = 2^{\frac{27}{3} } = 2^{9}$