Question

3x^2-4x-2=-3
resolva esta solucao

Answer 1

$3x^2-4x-2=-3\\\\\\ 3x^2-4x-2+3=0\to \\\\ 3x^2-4x+1=0 \\\\ a=3;b=-4;c=1\\\\\\ \Delta=b^2-4ac\to \Delta=(-4)^2-4*3*1\to \Delta=16-12\to \Delta=4\\\\ x' \neq x''\\\\ x= \frac{-b\pm \sqrt{\Delta} }{2a} \to x= \frac{-(-4)\pm \sqrt{4} }{2*1} \to x= \frac{4\pm 2 }{2} \to \\\\\\ x'= \frac{4+ 2 }{2} \to x'= \frac{6 }{2} \to x'=3\\\\\\ x''= \frac{4-2 }{2} \to x''= \frac{ 2 }{2} \to x''=1\\\\\\\\ S=(1;3)$