Question

Sabendo que log 2 = 0,30 e log 3 = 0,47 determine:
$log( \frac{25}{6} )$
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Answer 1

log 5= log(10/2)= log10-log2=1-0,3=0,7

log 25 =log 5² = 2.log5= 2(0,7)= 1,4

log6=log(2.3)=log2+log3=0,30+0,47=

0,77

log(25/6) =log25 - log6=1,4-0,77=0,63