Question

Alguém sabe resolver?

A)x²-3x-10=0
B)6x²+x-1=0
C)-3x²+8x+3=0
D)x²-4x-5=0
E)-x²+6x-9=0
F)x²-8x+12=0
G)-x²+2x+3=0
H)2x²-3x+1=0​

Answer 1

Temos que fazer Bhaskara para resolver

Use essa formula para responder

Δ=b²-4.a.c

x= (-b ±√Δ)/ 2.a

A)x²-3x-10=0

Δ=(-3)²-4.1.(-10)

Δ= 9+40

  =49

x=(-(-3)±√49)/ 2.1

x=(3±7)2

x'=3+7/2

x'=10/2=5

x"=3-7/2

x"= -4/2 = -2

B) Δ= 1²-4.6.(-1)

Δ=1+24

Δ=25

x=((-1)±√25)/2.6

x=1±5/12

x'=1+5/12

x'=6/12 = 1/2

x"=1-5/12

x"=4/12 = 1/3