Equação exponencial:
Raiz quintupla de 81 elevado a x = raiz quadrada de 3
korvo:
ATUALIZA A PÁGINA QUE VC VÊ MELHOR ;)
Respostas
respondido por:
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E ae manoo,
![( \sqrt[5]{81})^x= \sqrt{3}\\
(\sqrt[5]{3^4})^x= \sqrt[2]{3^1}\\
(3^{ \tfrac{4}{5} })^x=3^{ \tfrac{1}{2} }\\
\not3^{ \tfrac{4}{5}x}=\not3^{ \tfrac{1}{2} }\\\\
\dfrac{4}{5}x= \dfrac{1}{2}\\\\
x= \dfrac{1}{2}\div \dfrac{4}{5}\\\\
x= \dfrac{1}{2}\cdot \dfrac{5}{4}\\\\
x= \dfrac{5}{8}\\\\\\
\huge\boxed{\boxed{S=\left\{ \dfrac{5}{8}\right\}}}](https://tex.z-dn.net/?f=%28+%5Csqrt%5B5%5D%7B81%7D%29%5Ex%3D+%5Csqrt%7B3%7D%5C%5C%0A+%28%5Csqrt%5B5%5D%7B3%5E4%7D%29%5Ex%3D+%5Csqrt%5B2%5D%7B3%5E1%7D%5C%5C%0A%283%5E%7B+%5Ctfrac%7B4%7D%7B5%7D+%7D%29%5Ex%3D3%5E%7B+%5Ctfrac%7B1%7D%7B2%7D+%7D%5C%5C%0A%5Cnot3%5E%7B+%5Ctfrac%7B4%7D%7B5%7Dx%7D%3D%5Cnot3%5E%7B+%5Ctfrac%7B1%7D%7B2%7D+%7D%5C%5C%5C%5C%0A+%5Cdfrac%7B4%7D%7B5%7Dx%3D+%5Cdfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%0Ax%3D+%5Cdfrac%7B1%7D%7B2%7D%5Cdiv+%5Cdfrac%7B4%7D%7B5%7D%5C%5C%5C%5C%0Ax%3D+%5Cdfrac%7B1%7D%7B2%7D%5Ccdot+%5Cdfrac%7B5%7D%7B4%7D%5C%5C%5C%5C%0Ax%3D+%5Cdfrac%7B5%7D%7B8%7D%5C%5C%5C%5C%5C%5C%0A%5Chuge%5Cboxed%7B%5Cboxed%7BS%3D%5Cleft%5C%7B+%5Cdfrac%7B5%7D%7B8%7D%5Cright%5C%7D%7D%7D++++++++++++ "( \sqrt[5]{81})^x= \sqrt{3}\\
(\sqrt[5]{3^4})^x= \sqrt[2]{3^1}\\
(3^{ \tfrac{4}{5} })^x=3^{ \tfrac{1}{2} }\\
\not3^{ \tfrac{4}{5}x}=\not3^{ \tfrac{1}{2} }\\\\
\dfrac{4}{5}x= \dfrac{1}{2}\\\\
x= \dfrac{1}{2}\div \dfrac{4}{5}\\\\
x= \dfrac{1}{2}\cdot \dfrac{5}{4}\\\\
x= \dfrac{5}{8}\\\\\\
\huge\boxed{\boxed{S=\left\{ \dfrac{5}{8}\right\}}}")
Tenha ótimos estudos ;D
Tenha ótimos estudos ;D
Obrigado,me ajudou muito!
;D
Mas não seria 3³?(elevado a 3)
onde?
Esta certo obrigado
nds yyy
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