Question

sendo log2=x e log3=y calcular; a) log24 b) log9√8

Answer 1

Resposta:

a) y + 3x

b) 2y + $x^{3/2}$

Explicação passo-a-passo:

a) log 24 = log 3.2.2.2 = log3 + log2 + log2 + log2 = y + 3x

b) log9$\sqrt{8}$ = log 3.3.$\sqrt{2^3}$= log3 + log3 + log$2^{3/2}$ = 2y + $x^{3/2}$