• Matéria: Matemática
  • Autor: moniiArmy
  • Perguntado 9 anos atrás

Utilize a fórmula de Bhaskara:
×2-12×+ 36 = 0

Respostas

respondido por: guarischisa
1
delta= b²-4ac
delta=144-4.136 --> 144
x=12+-0/2
x=6

moniiArmy: Tenho que utilizar a fórmula de Bhaskara
respondido por: LuanaSC8
2
 x^{2} -12x+36=0\\\\ a=1;b=-12;c=36\\\\\\ \Delta=b^2-4ac\to \Delta= (-12)^2-4*1*36\to \Delta=144-144\to \Delta=0\\\\ x'=x''\\\\ x= \frac{-b\pm \sqrt{\Delta} }{2a} \to x= \frac{-(-12)\pm \sqrt{0} }{2*1} \to x= \frac{12\pm 0}{2} \to\\\\\\ x'=x''== \frac{12}{2} \tox'=x''=6\\\\\\\\ S=(6)
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