Question

bhaskara de -x2+12x-20=0 Alguem sabe?:

Answer 1

- x² + 12x - 20 = 0  (-1)
x² - 12x + 20 = 0

a = 1
b = - 12
c = 20

Δ = b² - 4.a.c
Δ = ( - 12)² - 4 . 1 . 20
Δ = 144 - 80
Δ = 64

x = - b + - √Δ  / 2a
x = - ( - 12) + - √64/ 2 . 1
x = + 12 + - 8/2
x' = 20/2  ⇒ x' = 10
x" = 4/2 ⇒ x" = 2

S = { 10 e  2} 

Answer 2

-x²+12x-20=0
a=-1 b=12 c=-20

Δ=b²-4.a.c
Δ=12²-4.-1.-20
Δ=144-80
Δ=64

x'=-b+√Δ/2.a
x'=-12+√64/2.-1
x'=-12+8/-2
x'=-4/-2
x'=2

x''=-b-√Δ/2.a
x''=-12-√64/2.-1
x''=-12-8/-2
x''=-20/-2
x''=10