Question

Qual a razão da PG cujo o primeiro termo é 81/8 e oitavo termo é 16/27

Answer 1

$a_{8}=16/27$
$a_{1}*q^{7}=16/27$
$(81/8)*q^{7}=16/27$
$q^{7}=(16/27)*8/81$
$q^{7}=(2^{4}/3^{3})*2^{3}/3^{4}$
$q^{7}=2^{7}/3^{7}$
$q^{7}=(2/3)^{7}$
$q= \sqrt[7]{(2/3)^{7}}$
$q=2/3$