Question

3-0 numero
complexo (1+i)^36​

Answer 1

(1+i)² = 1+2i+i² = 1+2i-1 = 2i

(1+i)^36= [(1+i)²]^18

(2i)^18

2^18.(i²)^9

2^18. (-1)^9

2^18. (-1)

- 2^18 ✓