Question

Calcule a soma dos infinitos termos da PG (32,8,2.....)

Answer 1

$a_{1}=32$
$a_{2}=8$

$q = a_{2}/a_{1}=8/32=1/4$

0 < |q| < 1: Soma infinita

$S_{n} = a_{1} / (1 - q)$
$S_{n} = 32 / (1 - [1 / 4])$
$S_{n}=32/([4 - 1]/4)$
$S_{n}=32/(3 / 4)$
$S_{n}=32*4/3$
$S_{n}=128/3$