Question

(x-3).(x+2)=4
por favor me ajudem!​

Answer 1

$(x-3).(x+2)=4 \\ {x}^{2} + 2x - 3x - 6 - 4 = 0 \\ {x}^{2} - x - 10 = 0$

$\Delta=1+40=41$

$x=\dfrac{1\pm\sqrt{41}}{2}\\x'=\dfrac{1+\sqrt{41}}{2}\\x''=\dfrac{1-\sqrt{41}}{2}$