Question

3 elevado 1,23 por favor ​

Answer 1

$x = {3}^{1,23} \\ log(x) = log({3})^{1,23} \\ log(x) = 1,23. log(3) \\ log(x) = 0,586 \\ x = {10}^{0,586} \\ x\approx 3,85$